C Program to Find the Destination using Coordinates and Directions

#include<stdio.h>
main()
{
#define MAXWIDTH   10           /* let's set the maximum width ... */
#define MAXHEIGHT  10          /* ... and the maximum height */

int  a[9][9];               /* Current coordinates */
char direction;         /* Direction of movement - N, S, E, W */
int distance;  /* Size of movement */
int  instructionCount;  /* Number of instructions */
int i,j;                 /* For-loop variable */
int x,y;
int t1,t2;
int b[0][0];

printf("Enter the start point (x,y): ");
scanf("%d",&a[0][0]);


//x%=MAXWIDTH; /* Make sure that the coordinates wrap so that they're still in the matrix */
//y%=MAXHEIGHT;
/* Read the number of moves */
printf("Enter the Number of Instructions n");
scanf("%d",&instructionCount);

/* process each instruction */
for(i=0; i<instructionCount; i++)
{
printf("Enter the no. of steps along with direction (e.g. 4N) n");
scanf("%d%c",&distance,&direction);
/* Now we increment/decrement according to the direction. However
* we have to stop when we hit the edges, i.e. can't go less than
* zero or greater than the width (for x) or height (for y);
*/
for(i=1;i<=2;i++)
{
for(j=1;j<=2;j++)
{
switch (direction)
{
/* North is upwards (towards the max) */
case 'n':
case 'N': a[i][j]=a[i-1][(i-1)+distance];
if (y > MAXHEIGHT)
y = MAXHEIGHT;
break;
/* South is down (towards zero) */
case 's':
case 'S': a[i][j]=a[i-1][(i-1)-distance];
if (y < 0)
y = 0;
break;

/* East is to the right (towards the max) */
case 'e':
case 'E': a[i][j]=a[(i-1)+distance][i-1];
if (x > MAXWIDTH)
x = MAXWIDTH;
break;

/* West is to the left (towards zero) */
case 'w':
case 'W':a[i][j]=a[(i-1)-distance][i-1];
if (x < 0)
x = 0;
break;

/* Something incorrect was provided */
default : printf("Error in input detectedn");
a[i][j]=b[0][0];
}
}
}

printf("The Final Destination is %dn", b[0][0]);
return 0; /* Needed to prevent a compiler warning */
}
}